# How do you graph #x+y=5# using intercepts?

##### 1 Answer

- Get the
#x# -intercept by setting#y=0# and solving for#x# . - Get the
#y# -intercept by setting#x=0# and solving for#y# .

Graph these two points, and connect them.

#### Explanation:

An **intercept** is simply a point where a line (or any function) crosses an axis. At such a point, the non-axis coordinate is 0. (e.g. all points on the

We can use this to help us get two points that are on the line, graph those two points, and finally connect them by drawing a line through them.

The

#color(white)(=>)x+y=5 " @ "y=0#

#=>x+0=5#

#=>xcolor(white)+color(white)0=5#

So, when

Similarly, to find the

#color(white)(=>)x+y=5 " @ "x=0#

#=>0+y=5#

#=>color(white)x color(white)+ y=5#

So when

Finally, we graph these two points, and connect them with a line:

graph{(x+y-5)((x-5)^2+y^2-0.06)(x^2+(y-5)^2-0.06)=0 [-8.325, 11.68, -2.3, 7.7]}

## Bonus:

For a linear equation of the form